Question

find the area of an equilateral triangle with side 8 cm. Also, find the area of the figure formed by placing another equilateral triangle of the same size along one of its sides. what is this figure called. find the length of diagonals​

Answer 1

here is your answer

lenght is 32root 3

i hope this answer helps you

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Answer 2

Answer:

The area of the  equilateral triangle  is 16√3cm².

Step-by-step explanation:

Each side of equilateral triangle=8cm

From the formula area of equilateral triangle $=\frac{\sqrt{3} }{4} a^{2}$

where a is side of eq. traingle

         area $=\frac{\sqrt{3} }{4} (8)^{2}$

Now   area   $=\frac{\sqrt{3} }{4} (64)\\=16\sqrt{3} cm^{2}$

If we combine another equilateral triangle, the shape formed called Rhombus.

The area of Rhombus = 2×area of equilateral triangle$=32\sqrt{3}cm^{2}$

Diagonal of Rhombus = length of side of equilateral triangle = 16√3cm