Question

Find the area of an irregular polygon field whose measures are as given in the figure

Answer 1

Answer:

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Answer 2

$the \: given \: field \: has \: 4 \: triangles \:$

$(1,3,4 \: and \: 5) \: and \: the \: trapezium \: (2)$

$area \: of \: the \: triangle \: 1= \frac{1}{2} \times b \times h = \frac{1}{2} \times 5 \times 6 = 15 {m}^{2}$

$area \: of \: the \: trapezium2 = \frac{1}{2} h(a + b) = \frac{1}{2} \times 13 \times (6 + 4) = 65 {m}^{2}$

$area \: of \: the \: triangle \: 3 \: = \frac{1}{2} \times b \times h = \frac{1}{2} \times 8 \times 4 = \frac{32}{2} = 16 {m}^{2}$

$area \: of \: the \: triangle \: 4 \: = \frac{1}{2} \times b \times h = \frac{1}{2} \times 13 \times 10=65m²$

$area \: of \: triangle \: 5 = \frac{1}{2} \times b \times h = \frac{1}{2} \times 13 \times 10 = 65 {m}^{2}$

$the \: total \: area \: of \: the \: field = 15 + 65 + 16 + 65 + 65 = 226 {m}^{2}$