Find the area of an isoceles triangle such that of two equal side be a and the angle included between them is 45°.
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Answer:
Area = base * height *1/2
Step-by-step explanation:
In triangle ABC,
AB=AC -----(1) (because in isoceles triangle two sides equal)
So, we can write this ,
AB =AB. ( From eq 1)
Area =1/2 *base *height
=1/2 *AB * AB
=1/2 Ans
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