find the area of an isoceles triangle the ratio of whose equalside to its base is 3:2 and perimeter is 32cm
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a being the equal side
(a/b)=3/2
perimeter=32
a+a+b=32
2a+b=32
2*(3/2)b+b=32
4b=32
b=8
a=12
s=32/2=16
√s*(s-a)*(s-b)*(s-c)
√16*4*8*4
16√8
area=32√2
(a/b)=3/2
perimeter=32
a+a+b=32
2a+b=32
2*(3/2)b+b=32
4b=32
b=8
a=12
s=32/2=16
√s*(s-a)*(s-b)*(s-c)
√16*4*8*4
16√8
area=32√2
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