Question

Find the area of an isoceles triangle whose equal sides are of length 15 cm each and the third side is 12 cm.

URGENT!!!!

Answer 1

Let the sides of the triangle be a,b, and c respectively.
a = b (Since it is isoceles, the 2 sides are equal)
a = 15 and b = 15, c = 12
Semi perimeter = (a + b + c) / 2
                       = 42/2 = 21 cm
Area = $\sqrt{s(s - a)(s - b)(s - c)}$
        = $\sqrt{21 * (21 - 15)(21 -15)(21 - 12)}$
        = $\sqrt{21*6*6* 9}$
        = $6\sqrt{21*3*3 }$
        = $6*3\sqrt{21}$cm²
        = 18√21cm² = 82.44cm²

Answer 2

Correct ans. is dis ..
Please see it .....