Find the area of an isoceles triangle whose one side is 4m greater than its equal sides and perimeter is 40m
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Answer:71.55m²
Step-by-step explanation:
Given
one side is 4m greater than its equal sides and perimeter is 40m
So let x be the two equal sides
So the another side will be x+4
So
(x+4)+2x=40
3x+4=40
x=12
So the sides are 12,12,16
Now by applying herons formula
S=40/2
=20
A=√s(s-a)(s-b)(s-c)
A=√20×8×8×4
A=71.55m²
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