Find the area of an isoceles triangle whoso perimeter is 32 and it's base is 12 cm.
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Let x be the equal side.
==>Perimeter:2x+12=32.
x=10cm.
Height of the base=8 (by solving using Pythagorean theorem).
Area of triangle=1/2*b*h.
Area of triangle =1/2*12*8.
Area of triangle=48cm^2.
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