Question

find the area of an isoceles triangle with perimeter 36 cm and base 16 cm.​

Answer 1

Answer:

HOPE IT MAY HELPS YOU

Step-by-step explanation:

Isosceles triangle

Solve for area

A=48cm²

b Base

16

cm

P Perimeter

36

cm

Using the formulas

A=bhb

2

P=2a+b

hb=a2﹣b2

4

Solving forA

A=1

4bP(P﹣2b)=1

4·16·36·(36﹣2·16)=48cm²

Answer 2

Answer:

The answer is 8$\sqrt{164$ (eight times the square root of 164),

or simplified, 16$\sqrt{41}$ (sixteen times the square root of 41)

Step-by-step explanation:

You know it's an isosceles triangle, which means that the other two sides are equal to each other, so you can find those sides by subtracting the base (16 cm) from the perimeter (36 cm) and dividing by two.

(36 - 16)/2 = 20/2 = 10       So the other two sides are both 10 cm.

Now you have to find the height, and for that you have to use the Pythagorean Theorem. So take half of the base (8 cm), that makes one side of the triangle, then take the one of the sides (10 cm), that makes the hypotenuse of the triangle, and then you just have to find the height (h) of the triangle, as follows:

h^2 = 8^2 + 10^2

h^2 = 164

h = $\sqrt{164}$

Now we can go for the area. The area of a triangle is 1/2(base * height).

1/2(16 * $\sqrt{164}$)  = 8$\sqrt{164}$ = 16$\sqrt{41}$