Question

find the area of an isocles triangle whose un equal side is 8 cm each equal side is 5 cm​

Answer 1

Answer:

Given,

Two Equal Sides = 5cm

Also,

Third Side = 8cm

So,

Semi-Perimeter

= (a + b + c)/2

= (5 + 5 + 8)/2

= (10 + 8)/2

= 18/2

= 9

Now,

Area of ∆ = √s(s - a)(s - b)(s - c)

Area of ∆ = √9(9 - 5)(9 - 5)(9 - 8)

Area of ∆ = √9(4)(4)(1)

Area of ∆ = √144

Hence,

Area of ∆ = 12 cm²

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