Question

find the area of an isoscele triangle whose one side is four meters greater than its equal side and perimeter is fourty meters​

Answer 1

Answer:

YOUR SOLUTION IS HERE .....

Step-by-step explanation:

let the two equal sides be x m

Another side is four metres greater than the equal sides i.e,= x+4 m

As per the given question ,

x + x + x + 4 = 40 m

=> 3x+ 4 = 40

=> 3x = 40-4

=> 3x = 36

=> x = 36/3

=> x = 12

So ,its sides are

x= 12

x = 12

x +4 = 16

Using Heron's formula ,

S = perimeter/2

=> 40/2

=> 20

Area =\/ S (s-a)(s-b)(s-c) [root over ]

=>\/ 20 (20-12)(20-12)(20-16) [" ]

=> \/ 20×8× 8 × 4

=> \/ 5120

=> 71.554 m

hope it helps u ..........

mark as the brainliest !!!!!!!!!

Answer 2

Step-by-step explanation:

how are you frnd .......