Question

find the area of an isoscelea triangle with sides 6cm, 8 cm and 8 cm. Find the area of an equilateral triangle whose, each side is 8 cm​

Answer 1

Step-by-step explanation:

equilateral triangle:- √3/4a²

√3/4×(8)²

√3/4×64

area of equilateral triangle:- 12√3

Answer 2

Answer:

for isosceles triangle:-

$a \: side = 6cm \:$

$c \: side \: = 8cm$

Using formula

$s = a + \: b + \: c \\ \2$

=6+8+8/2

= 22/2 = 11

By using Heron's formula

=22/2

= 11

Using heron 's formula

$area \: of \: triangle \: = \sqrt{s(s \: - a \: } )(s - b \: ) \: (s - c)$

$\sqrt{11(11 - 6)(11 - 8)(11 - 8)}$

$\sqrt{495}$

$= 22.2482955cm ^{2}$

for equilateral triangle:-

A=3

4a2=3

4·82≈27.71281