Find the area of an isosceles ΔABC in.
which BC=8cm and AC=AB=5cm . If CE perpendicular to AB, find CE.
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find x using pythagorus therom .
and then use formual 1/2 base x height
ans is 12 cm2
and then use formual 1/2 base x height
ans is 12 cm2
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Hypotenuse=8cm base =5cm
H^2=b^2+h^2
8^2=5^2+h^2
64=25+ h^2
H^2=64-25
h^2=39
h=6.24
Area =1/2*base* height
=1/2*5*6. 24
=15.6cm^2
H^2=b^2+h^2
8^2=5^2+h^2
64=25+ h^2
H^2=64-25
h^2=39
h=6.24
Area =1/2*base* height
=1/2*5*6. 24
=15.6cm^2
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