Question

Find the area of an isosceles right angle triangle if one of the right sides is 20 cm long​

Answer 1

$\bf{\underline{\underline {Answer:}}}$

$\bf {∴Area \:of \:an \:isosceles\: right \:angle\: triangle} \bf=200{cm}^{2}$

$</strong><strong>\</strong><strong>bf</strong><strong> </strong><strong>{</strong><strong>\</strong><strong>underline</strong><strong>{</strong><strong>\underline{Step\: by\: step\: </strong><strong>explanation</strong><strong>:</strong><strong>}}}$

$\bold{\underline {Given:}}$

${⟹}{One \:right\: side\: is\: 20 cm}$

$\bold{\underline {To \:find:}}$

${⟹}{Area\: of\: an\: isosceles\: right\: angle \:triangle = \:?}$

Since, In isosceles right angle triangle two sides are equal :

So, Base = 20 cm

Height =20 cm

Now,

By using the isosceles right angle triangle area formula:

Area isosceles right angle triangle $= \dfrac{1}{2}×Base×height$

$= \dfrac{1}{2}×20×20$

$\bf=200{cm}^{2}$

$\huge\bf\mathbb {Solved}$

#Be_Brainly

Answer 2

=

2

1

×Base×height

= \dfrac{1}{2}×20×20=

2

1

×20×20

\bf=200{cm}^{2}=200cm

210