Find the area of an isosceles right angled triangle whose each of equal sides is 10 cm long.
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If it is an isosceles right triangle, all that means is that the two smaller angles are congruent and the two legs are congruent. So, you can flip the triangle on its side so that the base is one of the legs that are 10 cm. Then, the base of the triangle is 10 cm and the height is also 10 cm. Now we can easily find the area:
A = 1/2∗bh
A = 1/2∗(10×10)
A = 1/2∗100
A = 50
Therefore, the area of the triangle is 50 cm 2
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