Question

Find the area of an isosceles right triangle having the length of each equal side 5 cm​

Answer 1

$\bf{\huge{\underline{\boxed{\sf\red{Answer: 12.5\:cm^2}}}}}$

Given :

• Length of an isosceles right triangle = 5 cm

To Find :

• Area of the given triangle

$\huge\underline\green{\tt Solution:}$

→ Area of triangle

$= \dfrac{1}{2}\times base\times height$

$=\dfrac{1}{2}\times {5}\times{5}$

$=\dfrac{1}{2}\times 25$

$= \dfrac{25}{2}$

∴ Area = $12.5\: cm^2$

Answer : Area of the given triangle is $12.5\: cm^2$

Answer 2

$\huge\tt\orange{SoLUtiOn:-}$

Given that :-

$\star$base = 5cm

$\star$height = 5cm

Then according to questions:-

using formula:

$\huge\boxed{\orange{ Area \:of \:triangle \: = \frac{1}{2} × base × height }}$

$Area \: of \: a \: triangle = \frac{1}{2} × 5cm × 5cm \\ \\ Area \: of \:a \: triangle = \frac{25{cm}^{2}}{2} \\ \\ Area\: of\: triangle\: = 12.5{cm}^{2}$