Find the area of an isosceles right triangle
having the hipotenuce of length 30 cm
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Answered by
19
Given that
An isoceles right angled triangle, with hypotenuse = 30 cm
Let the other two equal sides be a (since it's isoceles, other two sides will be equal)
By Pythagoras Theorem, we know that,
base² + height² = Hypotenuse², hence
a² + a² = 30²
=> 2a² = 900
=> a² = 900/2
=> a² = 450 cm²
Now, area of right angled isoceles triangle = 1/2 × base × height
= 1/2 × a × a
= a²/2
So, we have a² = 450,
area = 450/2 = 225 cm²
Answer :- 225 cm²
An isoceles right angled triangle, with hypotenuse = 30 cm
Let the other two equal sides be a (since it's isoceles, other two sides will be equal)
By Pythagoras Theorem, we know that,
base² + height² = Hypotenuse², hence
a² + a² = 30²
=> 2a² = 900
=> a² = 900/2
=> a² = 450 cm²
Now, area of right angled isoceles triangle = 1/2 × base × height
= 1/2 × a × a
= a²/2
So, we have a² = 450,
area = 450/2 = 225 cm²
Answer :- 225 cm²
Answered by
4
hypotenuse = 30 cm
since , it is isosceles right triangle
2x^2 = 30 x 30
x ^ 2 = 30 x 30 / 2
X ^2 = 450
X = √450
Area of isosceles right triangle = 1/2 *base * height
= 1/2 x √450 x√450 = 1 / 2 x 450 = 225sq cm
I think so that's your answer.
Hope this helps you.☺
since , it is isosceles right triangle
2x^2 = 30 x 30
x ^ 2 = 30 x 30 / 2
X ^2 = 450
X = √450
Area of isosceles right triangle = 1/2 *base * height
= 1/2 x √450 x√450 = 1 / 2 x 450 = 225sq cm
I think so that's your answer.
Hope this helps you.☺
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