Math, asked by CapBlissSaigi8692, 11 months ago

Find the area of an isosceles right triangle if one of its right side is 18 cm long

Answers

Answered by jkutz
47

area = (1/2)bh

= (1/2) × 18 × 18

= 324/2

= 162 cm square..

Answered by 23saurabhkumar
36

Answer:

Area of the triangle is 162 square cm.

Step-by-step explanation:

In the question,

We have been provided a right angled isosceles triangle with the length of the side = 18 cm

Now,

We know that,

Area of the isosceles right angle triangle is,

A=\frac{1}{2}\times base \times height

Because, it is an isosceles triangle we know that the length of the base and the height are going to be same.

So,

A=\frac{1}{2}\times 18\times 18=18 \times 9 = 162cm^{2}

Therefore, the Area of the triangle is 162 square cm.

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