Question

Find the area of an isosceles right triangle , if one of its right side is 18 cm long

Answer 1

Given,

It's a right angles triangle

where AB = 18 cm

AB = BC ( as they r isosceles triangle, two sides are equal)

So AB = BC = 18cm

AB = height of the triangle

BC = Base of the triangle

We know,

Area of a right angled triangle = ½ bh

$= \frac{1}{2} \times b \times h \\ \\ = \frac{1}{2} \times 18 \times 18 \\ \\ = 9 \times 18 \\ \\ = 162$

Hence the area of the isosceles right angled triangle is 162 cm²

Answer 2

The answer is 162

hope it helps