Find the area of an isosceles right triangle of equal sides 40 cm each.
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Answered by
44
hey buddy here is your simple solution
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area of an right angled triangle is 1/2×b×h
(b= base and h= height)
so given base = height =40 cm
so area = 1/2×40×40
= 800 cm ^2
thanks
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ASK BELOW FOR DOUBTS ⬇⬇⬇
__________________
area of an right angled triangle is 1/2×b×h
(b= base and h= height)
so given base = height =40 cm
so area = 1/2×40×40
= 800 cm ^2
thanks
________________________
ASK BELOW FOR DOUBTS ⬇⬇⬇
Answered by
8
An isosceles right triangle whose equal sides are 40 cm each.
∴The base will be= 40 cm
The height will be = 40cm
We know the formula of the area of an right angled triangle = ×b×h
(b= base =40cm
and h= height= 40cm)
so area = ×40×40
= 800 cm²
∴ The area of an isosceles right triangle of equal sides 40 cm each will be 800 cm²
Ans:- The area of an isosceles right triangle of equal sides 40 cm each will be 800 cm².
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