Question

find the area of an isosceles right triangle whose base is 450 cm

Answer 1

Answer:

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Answer 2

$\large{\red{\underline{\tt{Diagram\::-}}}}$

$\setlength{\unitlength}{1.5cm}\begin{picture}(6,2)\put(7.7,2.9){\large{A}}\put(7.7,1){\large{B}}\put(10.6,1){\large{C}}\put(8,1){\line(1,0){2.5}}\put(8,1){\line(0,2){1.9}}\put(10.5,1){\line(-4,3){2.5}}\put(7.1,2){\tt{\large{450cm}}}\put(9,0.7){\tt{\large{450cm}}}\put(8.2,1){\line(0,1){0.2}}\put(8,1.2){\line(3,0){0.2}}\end{picture}$

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★ Given : Right angled isosceles triangle with base 450 cm.

Hence, base = height

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$\underline{\bigstar\:\textbf{According to the Question :}}$

${\dag}\:\underline{\textsf{Area of Triangle ABC :}}$

$\begin{lgathered}\dashrightarrow\tt\:\:Area_{{\tiny\triangle ABC}}=\dfrac{1}{2} \times Base \times Height\\\\\\\dashrightarrow\tt\:\:Area_{{\tiny\triangle ABC}} =\dfrac{1}{2} \times 450\:cm \times450 \:cm\\\\\\\dashrightarrow\tt\:\:Area_{{\tiny\triangle ABC}} = \dfrac{1}{2}\times 202500\\\\\\\dashrightarrow\:\:\underline{\boxed{\tt Area_{{\tiny\triangle ABC}} = 1012500 \:cm^{2}}}\end{lgathered}$

$\therefore\:\underline{\textsf{Area of Triangle ABC is \textbf{1012500}}\:\sf{cm^2}}.$

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