Question

Find the area of an isosceles right triangle
whose one equal side is 4 1 by 2m.​

Answer 1

Answer:

2.5

Step-by-step explanation:

Answer 2

ANSWER:

Given

• Equal side of the given right isosceles traingle

Let us consider

∆ABC

Right angle at B

AB = BC

Area of right angled isosceles triangle = ½×base²

Here

Base = 4½cm = 4.5cm

Ar(∆) = ½(4.5)² = ½(20.25)

Ar(∆) = 10.125

Hence area of given isosceles right triangle is = 10.125cm²

MORE INFORMATION:

→ Area of rectangle = length × breath

→ Perimeter of rectangle = 2(length + breath)

→ Area of triangle = 1/2 × base × height

→ Perimeter of square = 4(side)

→ Area of square = side²