Find the area of an isosceles right triangle with hypotenuse 40 cm
Answers
Answered by
66
Since it's an isoceles triangle, the other two sides would be equal. Let them be of "a" cm
So by Pythagoras Theorem,
Base² + Height² = Hypotenuse²
=> a² + a² = 40²
=> 2a² = 1600
=> a² = 1600/2
=> a² = 800
Now the area for isoceles right triangle is
1/2 × base × height
But since base = height = a
=> area = 1/2 × a × a
=> area = 1/2 × a²
=> area = 1/2 × 800
= 400 cm²
Answer :- 400
So by Pythagoras Theorem,
Base² + Height² = Hypotenuse²
=> a² + a² = 40²
=> 2a² = 1600
=> a² = 1600/2
=> a² = 800
Now the area for isoceles right triangle is
1/2 × base × height
But since base = height = a
=> area = 1/2 × a × a
=> area = 1/2 × a²
=> area = 1/2 × 800
= 400 cm²
Answer :- 400
Answered by
22
Hi Mate!!!!
Area of isosceles right Trangle is = 1 / 2 ( b )×( h )
here in isosceles triangle b = h
So,
it's area is = 1 / 2 ( h² )
By Pythagoras theorem.
( 40 )² = h² + h²
2h² = 1600
h² = 800cm²
Therefore area of isosceles right Trangle is
1 / 2 ( 800cm² ) = 400cm²
Have a nice day ahead..
Area of isosceles right Trangle is = 1 / 2 ( b )×( h )
here in isosceles triangle b = h
So,
it's area is = 1 / 2 ( h² )
By Pythagoras theorem.
( 40 )² = h² + h²
2h² = 1600
h² = 800cm²
Therefore area of isosceles right Trangle is
1 / 2 ( 800cm² ) = 400cm²
Have a nice day ahead..
Similar questions