Question

find the area of an isosceles traingle whose equal sides are 12cm each and the perimeter is 30cm

Answer 1

Hi Mate!!!

Let the third side be = x

x + 24 = 30 Given

x = 30 -24

x = 6

So, sides are 12cm,12cm and 6cm


Itz area = √{ s ( s - a ) ( s - b ) ( s - c )} { Heron's formula}

s = 30/2 = 15cm

a = 12 , b = 12 c = 6


Area = √ {15 ( 3 ) ( 3 ) ( 9 )}

Area = 9 (√15 ) cm²

Have a nyc tym...

Answer 2

Heron's Formula =>
$\sqrt{s(s - a)(s - b)( s - c) }$
Where s is the semipeimeter and a,b and C are sides

Given Perimeter = 30 cm

=> S = 30/2

=> S = 15 cm

Third side = ??

We know, perimeter = sum of sides

=> 12 + 12 + side = 30

=> third side = 30 - 24

=> third side = 6 cm

=> Area =
$\sqrt{15(15 - 12)(15 - 12)(15 - 6)} \\ \\ = > \sqrt{15 \times 3 \times 3 \times 9} \\ \\ = > 3 \times 3 \times \sqrt{15} \\ \\ = > 9 \sqrt{15}$



Hence, area = 9√15 cm²