Question

Find the area of an isosceles trapezium ABCD where AB is 10cm, BC and AD is 20cm and DC is 42 cm.

Answer 1

Answer:

82000 cm^2

Step-by-step explanation:

area = side × side × side× side

= 10× 10× 20× 42

= 100 × 820

= 82000cm^2