Question

Find the area of an isosceles trapezium with
lege 25 cm and bases
16 cm and 30cm.​

Answer 1

Answer:

575cm^2

Step-by-step explanation:

parallel sides=16cm and 30cm

height of trapezium=25cm

area of trapezium=1/2(16+30)25cm^2

=1/2(46)25cm^2

=(23)25cm^2

=575cm^2