Question

find the area of an isosceles triangle ABC having base BC as 8 cm and AB=AC=5cm
the altitude of AABC on the base BC.​

Answer 1

Answer:

area of triangle =√s(s-a) (s-b) (s-c)

Step-by-step explanation:

s=a+b+c/2

s=8+5+5=18 cm

√18*10*13*13

3*2*13√5cm²

78√5 cm²

thanks