Question

Find the area of an isosceles triangle ABC in which AB = AC = 5 cm and BC = 8 cm

Answer 1

Step-by-step explanation:

AB=AC=5cm

BC=8cm

area of iscoceles triangle= bh/2

draw AD perpendicular to BC

BY Pythagorean theorem

AB²=BD²+AD²

5² = 4²+AD²

AD = 3cm

area=3×8/2

=12cm²

Answer 2

Answer:

4√39

Step-by-step explanation:

first apply Pythagoras theorem,

divide BC into two equal halves and name the midpoint be D

AB^2--BD^2=AD^2