Find the area of an isosceles triangle,each of whose equal side is 13cm and base 24cm.
Answers
Answered by
33
first and second side=13cm (a and b)
third side=24 (c side)
semi perimeter =13+13+24/2= 25
area of triangle = √s(s-a)(s-b)(s-c)
√25(25-13)(25-13)(25-24)
√25×12×12×1
√5×5×2×2×3×2×2×3
60 sq. cm
third side=24 (c side)
semi perimeter =13+13+24/2= 25
area of triangle = √s(s-a)(s-b)(s-c)
√25(25-13)(25-13)(25-24)
√25×12×12×1
√5×5×2×2×3×2×2×3
60 sq. cm
jaswinderkaur1:
a*2 + b*2 =( a+ b) *2
(a+ b )* 2 = 35*2
a*2 + b*2 + 2ab= 35*2
2ab =35*2 - (a*2 + b*2)
2ab = 35*2 - 25* 2. { as a*2 + b*2 = 25 , Pythagoras thorem
2ab = 1225 - 625 =600
ab = 300
Now , Area of triangle = 1/2 × ab { as a = base , b= height, perpendicular}
area = 1/2 × 300
area = 150
Answered by
27
Answer: 60cm^2
Step-by-step explanation:
Attachments:
Similar questions