Question

find the area of an isosceles triangle each of whose equal side is 18 cm and base is 28 cm​

Answer 1

Answer:

252

Step-by-step explanation:

Multiply 18 by 28 to get 504.

Now since that triangle is half a square divide 504 by two to get 252.

Answer 2

Step-by-step explanation:

$area = \\ \sqrt{s(s - a)(s - b)(s - c)} \\ s = \frac{a + b + c}{2}$

$s = \frac{18 + 28 + 28}{2} \\ = \frac{84}{2} = 42$

$area = \\ \sqrt{42(42 - 18)(42 - 18)(42 - 28)} \\ \sqrt{42 \times 24 \times 24 \times 14} \\ 17 \times 24 \sqrt{3} \\ 336 \sqrt{3}$

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