Question

Find the area of an isosceles triangle each of whose equal sides 10 cm and whose base is 20 cm

Answer 1

Answer:

Step-by-step explanation:

1/2 * b*h

1/2 * 10*20

200/2

100

Answer 2

ABC is an isoceles triangle,

AB=10 cm

AC=10 cm

BC=20 cm

so,

Angle ABC=90 degree

Area of isoceles triangle ABC=1/2*b*h

b=10 cm

h=20 cm

therefore,

area=1/2*10*20

=5*20

=100 cm sq