Question

find the area of an isosceles triangle each of whose equal sides measures 13cm and whose measures 20 cm​

Answer 1

We have three sides- 13cm,13cm and 20cm, you can easily find the perimeter by using heron's formula

 First of all- we need to get the semi-perimeter

s=a+b+c/2=13+13+20/2

=46/2=23

now, put the heron's formula i.e. √s(s-a)(s-b)(s-c)

=√23(23-13)(23-13)(23-20)

=√23*10*10*3

=√23*2*5*2*5*3

=10√23*3

=10√69

=83.07cm^2 (approx.)

Answer 2

Step-by-step explanation:

To find area,

we use heron's formulae,

a=13cm. b=13cm. c=20cm.

peri.= sum of all sides =13+13+20=46cm

s=p/2. =46/2cm. =23 cm.

area of a triangle=√s(s-a)(s-b)(s-c)

=√23(23-13)(23-13)(23-20)

=√23×10×10×3

=10√23×3

=10√69 cm^2 answer.