Question

Find the area of an isosceles triangle each of whose equal sides measures 13cm and whose base measures 20 cm

Answer 1

Heya........!!!

This question can be solved by using Herons formulae

Given :

Equal side = 13 cm
Base = 20 cm

=> Semi-perimeter = s=a+b+c/2=13+13+20/2
=46/2=23

Now , substituting values in Herons formulae we get ,,

Herons formulae = √s(s-a)(s-b)(s-c)

Putting the values of s and a,b,c we get :

=> √23(23-13)(23-13(23-20)
=> √23×10×10×3
=> √23×2×5×2×5×3
=> 10√23×3
=> 10√69
=> 83.07cm^2 

➡Area of isosceles triangle = 83.07 cm^2




Hope It Helps You ^_^

Answer 2

half *base *hieght
1/2*base(20)*hieght($\sqrt{69}$) ie 13*13-10*10(pythagoras theorm)
1/2*20$\sqrt{69}$
ans=10$\sqrt{69}$ or  10*8.3066 or 83.066..
hope it helps u and make me brainliest if u feel it useful