Question

Find the area of an isosceles triangle, each of whose equal sides is 13 cm and whose base is 24 cm. Also find its altitude corresponding to unequal side.​

Answer 1

Answer:

We have,

Three sides13cm,13cm and 20cm.

By using Heron's formula

We  need to get the semi-perimeter

s=2a+b+c=213+13+20

=246=23

Now,

put the  heron's formula,

s=s(s−a)(s−b)(s−c)

=23(23−13)(23−13)(23−20)

=23×10×10×3

=1023×3

=83.07cm2

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

=83.07$cm^{2}$

Answer:

s=$\frac{a+b+c}{2}$=$\frac{13+13+20}{2}$=23

By using Heron's formula

area=$\sqrt{s(s-a)(s-b)(s-c)}$

        =$\sqrt{23(23-13)(23-13)(23-20)}$

         =$\sqrt{23*10*10*3}$

        =$\sqrt{6900}$

         =83.07$cm^{2}$