Question

Find the area of an isosceles triangle, each of whose equal sides is 13 cm and whose base is
24 cm. Also find its altitude corresponding to unequal side.​

Answer 1

Answer:

Area=60 cm², Altitude=5cm

Step-by-step explanation:

It is given that

sides of the triangle are 13 cm, 13cm, and 24cm

We know that Area of triangle

=√[s×(s-a)×(s-b)×(s-c)]

where s=semiperimetre or half of perimeter

=13+13+24/2=25cm

And a,b and c are sides of triangle

According to the formula

=√[25×(25-13)×(25-13)×(25-24)

=√25×12×12×1

=√5×5×12×12×1. (because 5×5 is equal to 25)

=5×12

=60

Now altitude,

Another area of triangle=1/2×base×altitude

=60cm

Here base=24 cm

altitude=60×2/24

=5cm

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