Find the area of an isosceles triangle each of whose equal side measure 13cm and whose base measure 20cm
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We drop a perpendicular from the vertex.
Call it lenght h
We know that this line divises the base into 2 equal parts.
From pythagoras theorem,
10²+h²=13²
100+h²=169
h²=69
h=√69
Area of a triangle is 1/2xbxh
=1/2x20x√69
=10√69 sq cm
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