find the area of an isosceles triangle each of whose equal sides is 13 cm and whose base is 24 cm
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Refer to the above attachment
Two methods are done
Two methods are done
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cckiller20:
by heron's formula
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according to herones formula
A=√s(s-a)(s-b)(s-c)
s=(a+b+c)/2.
where a=b=13; c=24
s=(13+13+24)/2=50/2=25
A=√25(25-13)(25-13)(25-24)
=√25×12×12×1
=5×12
=60 sq.cm
A=√s(s-a)(s-b)(s-c)
s=(a+b+c)/2.
where a=b=13; c=24
s=(13+13+24)/2=50/2=25
A=√25(25-13)(25-13)(25-24)
=√25×12×12×1
=5×12
=60 sq.cm
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