Question

find the area of an isosceles triangle each of whose equal sides is 13 cm and whose base is 24 cm

Answer 1

Refer to the above attachment

Two methods are done
$\red{Be\:Brainly}$

Answer 2

according to herones formula

A=√s(s-a)(s-b)(s-c)

s=(a+b+c)/2.

where a=b=13; c=24

s=(13+13+24)/2=50/2=25

A=√25(25-13)(25-13)(25-24)

=√25×12×12×1

=5×12

=60 sq.cm