Question

find the area of an isosceles triangle each of whose sides equal sides measure to 13 cm and whose base measures to 20 CM​

Answer 1

first draw the diagram

then find s=( a+b+c)/2

then by the herons formulae find whole √s(s-a) (s-b) (s-c)

then you will get your answer.

hope you understand my answer. please mark me brainlist

Answer 2

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Solution

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$\rm \: here \: each \: equal\: side \: \: a = 13cm \: and \: base = 20cm \\ \\ \therefore \rm \: area \: of \: the \: triangle = \big({ \frac{1}{4} b. \sqrt{4a {}^{2} - b {}^{2} } } \big)cm {}^{2} \\ = \big( \frac{1}{4 } + 20 \times \sqrt{4 \times 169 - 20 \times 20} \big) cm {}^{2} \\ = 83.07 \: cm {}^{2}$