Math, asked by deepakoshi18, 10 months ago

find the area of an isosceles triangle having base 2cm and the length of its equal side 4cm​

Answers

Answered by shantinathdhonde145
2

Answer:Area of triangle is √15cm^2

Step-by-step explanation:As its base is 2cm

And by taking line perpendicular to base from its opposite point it is its height. it forms a right angled triangle

By using pythagoras theorem we get its height which is equal to √15 cm

Are of triangle =0.5* 2*√15=√15 cm^2

Answered by azizalasha
0

Answer:

Step-by-step explanation:

height = √16 - 1 = √15

area = 2√15/2 = √15 cm²

Similar questions