Math, asked by abhijeet7162, 5 months ago

Find the area of an isosceles triangle having
base 2cm and the length of one is the equal sides
is 4cm​

Answers

Answered by ranviki
3

Answer:

√15cm²

Step-by-step explanation:

One side = 2cm

In isosceles triangle two sides are equal, So two sides = 4cm

S = 2+4+4/ 2 = 5 cm

therefore, area of isosceles triangle = √s(s-a)s(s-b)s(s-c)

= √5(5-2)(5-4)(5-4) = √5(3)(1)(1)

= √15cm²

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