Find the area of an isosceles triangle having
base 2cm and the length of one is the equal sides
is 4cm
Answers
Answered by
3
Answer:
√15cm²
Step-by-step explanation:
One side = 2cm
In isosceles triangle two sides are equal, So two sides = 4cm
S = 2+4+4/ 2 = 5 cm
therefore, area of isosceles triangle = √s(s-a)s(s-b)s(s-c)
= √5(5-2)(5-4)(5-4) = √5(3)(1)(1)
= √15cm²
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