find the area of an isosceles triangle having base 2cm and the length of one side is equal side is 4cm
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Answered by
30
s =a+b+c/2
=4+4+2/2
=5cm
area=√s(s-a)(s-b)(s-c)
=√5(1)(1)(3)
=√15
=3.9 cm² (approx)
=4+4+2/2
=5cm
area=√s(s-a)(s-b)(s-c)
=√5(1)(1)(3)
=√15
=3.9 cm² (approx)
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18
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