Find the area of an isosceles triangle having base 3 cm and length of one of the equal sides is 5 cm.
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4
Answer:
base=3cm
equal sides=5cm,5cm
semi perimeter, s = a+b+c/2=3+5+5/2 CM =13/2cm=6.5cm
Area of triangle=√s(s-a) (s-b) (s-c)
= √6.5(6.5-3)(6.5-5)(6.5-5)
=√6.5*3.5*1.5*1.5
=√5*1.3*5*0.7*1.5*1.5
=5*1.5√1.3*0.7
=7.5√0.91
=7.5*0.9539
=7.1545..
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0
Answer:
1.5√22.75 = 7.15
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