Find the area of an isosceles triangle having base 4cm and length of one of equal sides as 6cm
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Answer:
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Step-by-step explanation:
Sides = 6cm , 6cm ,4cm => s= 16/2=>8
therefore area =
\sqrt{8} (8 - 6)(8 - 6)(8 - 4)
\sqrt{8 \times 2 \times 2 \times 4}
=>
8 \sqrt{2} \: cm2
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