Question

Find the area of an isosceles triangle having perimeter 32cm and

length of the unequal side is 12 cm.​

Answer 1

Answer

Let △ABC be an isoceles △, such that AB=BC perimeter =a+12+a=2a+12

Also, 2a+12=32cm⇒a=232−12=10cm

∴ar△ABC=s(s−a)(s−b)(s−c),s=2a+b+c=232=16cm

                                 =16(16−10)(16−10)(16−12)=16×6×6×4=4×6×2

                                 =48cm2

Answer 2

here is your answer... I hope it will be help you