Question

find the area of an isosceles triangle having the base 6cm and the length of each side 5cm .

Answer 1

Answer:

12 cm²

Step-by-step explanation:

Base = 6 cm

Equal sides = 5cm

Draw perpendicular on base from top vertex

Perpendicular Height = √ ( 5² -(6/2)²) = √(25-9)  = √16 = 4cm

Area = (1/2)* Base * perpendicular height

= (1/2)* 6 * 4 = 12 cm²

Answer 2

IN AN ISOCELES TRIANGLE MEASURE OF TWO SIDES ARE EQUAL = 5 cm
another side = 6 cm
SO, SEMI PERIMETER= 10+6/2 = 8cm
BY APPLYING HERON'S FORMULA,
√8(8-5)^2×(8-6) cm^2
=√2^4× 3^2 cm^2
= 4× 3 cm^2
= 12 cm^2