Question

find the area of an isosceles triangle if its base is 16 cm and one of its equal sides is 17 cm long.​

Answer 1

Answer:

120^2

Explanation:

The third side will be 17+17+16= 50

S= 50/2 = 25

by using herons formula

$\sqrt{25(25 - 17)(25 - 17)(25 - 16)}$

$\sqrt{25 \times 8 \times 8 \times 9}$

$\sqrt{5 \times 5 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3}$

Now multiply by taking common from these:-

=5×2×2×2×3

=120 cm^2