Find the area of an isosceles triangle if its base is 16 cm and one of its equal sides is 17 cm long. ans this correct then i will definetly mark you brainliest
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Step-by-step explanation:
base=16cm
each equal side=17cm
area of isosceles triangle=b/4{square rootof4asquare-bsquare}
16/4{square root of 4×(17)square-16square}
4{square root of( 1156-256)}
4×squre root of 900
4×30=120sqcm
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