Question

find the area of an isosceles triangle if length of its equal side is 10cm and length of its third side is 16cm? ​

Answer 1

Answer:

if ABC isosceles triangle with AB=AC then if draw a median from vertices a that will be also height which perpendicular to base

so it divides base into two equal parts and perpendicular to base

so AC^2 = AD^2+CD^2(if we consider the point D as midpoint)

10^2= AD^2+8^2

100=AD^2+64

AD^2=100-64=36

AD=6

so area of the triangle =1/2*base*height

=1/2*16*6

=48