Question

find the area of an isosceles triangle in which each of the equal sides measures 30cm and the third side is 48 cm long​

Answer 1

◆【SOLUTION】◆

If a triangle have sides a,b,c then the area of the triangle can be written as.....

♀ √s(s-a)(s-b)(s-c) ♀

where s = (a+b+c)/2

Acc to your question

a = 48cm

b = 30cm

c = 30cm

s = (48 + 30 + 30)/2

s = 54cm

(s - a) = 54 - 48 = 6cm

(s - b) = 54 - 30 = 16cm

(s - c) = 54 - 30 = 16cm

∆ = √54(6)(16)(16)

∆ = √(3)²(6)²(16)²

∆ = 3×6×16

◆【Area = 288cm²】◆

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