Question

Find the area of an isosceles triangle in which each of the equal sides measures 30 cm and the
third side is 48 cm long.​

Answer 1

Step-by-step explanation:

by Herons formula ,

$\sqrt{s(s - a)(s - b)(s - c)}$

$s = \frac{a + b + c}{2}$

s = 108/2

s = 54

therefore,

$\sqrt{54(54 - 30)(54 - 30)(54 - 48)}$

$= \sqrt{54(24)(24)(6)}$

$= \sqrt{186624}$

$= \: 432 \: sq.m$

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