Find the area of an isosceles triangle in which each of the equal sides measures 30 cm and the third side is 48 cm long.
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Answered by
166
formula of hieght=square root of a square -b square/4 where a=one equal side and b= base
height=18cm
base=48cm
equal side=30cm
area 1/2*base*height
=1/2*48*18
=24*18
=432cm square
hope this will help you and give thanks and tap on brainliest plzzzz....
height=18cm
base=48cm
equal side=30cm
area 1/2*base*height
=1/2*48*18
=24*18
=432cm square
hope this will help you and give thanks and tap on brainliest plzzzz....
bittu41:
plz give....
Answered by
16
Answer:
432 cm ^2
Step-by-step explanation:
Hope it is useful for you
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